Instruction

1

The specific

C = Q/m(T_2-T_1)

Unit of specific heat capacity has the units in the system SI – (j/kg*K).

**heat capacity**of a substance is the quantity of heat required to heat or cool 1 kg of substance by 1 Kelvin. That is, in other words, if for example the specific heat of water is equal to 4.2 kJ/(kg*K) means that in order to heat one kg of water by one degree, you must pass this kg of water is 4.2 kJ of energy. Specific heat of a substance is given by:C = Q/m(T_2-T_1)

Unit of specific heat capacity has the units in the system SI – (j/kg*K).

2

The specific heat of a body is determined experimentally by using a calorimeter and thermometer. A simple calorimeter consists of a polished metal Cup, then put inside the other metal of glass tubes (for heat insulation) and filled with water or other liquid with known specific

**heat capacity**. Body (solid or liquid), heated to a certain temperature t, is immersed in a calorimeter where temperature is measured. Let the test lowering of the body temperature of the liquid in the calorimeter was equal to t_1, and after the temperature of the water (liquid) and lowered into it the body will be equal, it will be equal ?.

3

From the law of conservation of energy it follows that the heat Q given to the heated body, equal to the amount of heat Q_1 obtained with water, and Q_2 obtained by the calorimeter:

Q=Q_1+Q_2

Q=cm(t- ?), Q_1=c_1 m_1 (?-t_1), Q_2=c_2 m_2(?-t_1)

cm(t- ?)= c_1 m_1 (?-t_1)+ c_2 m_2(?-t_1)

here m_1 and c_1 - specific heat and mass of water in the calorimeter, and c_2 m_2 - specific heat and mass of the material of the calorimeter.

This equation expresses the balance of thermal energy, is called the equation of thermal balance. He will find

c=(Q_1+Q_2)/m(t- ?) =( c_1 m_1 (?-t_1)+ c_2 m_2(?-t_1))/m(t- ?) = (c_1 m_1+m_2 c_2)( ?- t_1)/m(t- ?)

Q=Q_1+Q_2

Q=cm(t- ?), Q_1=c_1 m_1 (?-t_1), Q_2=c_2 m_2(?-t_1)

cm(t- ?)= c_1 m_1 (?-t_1)+ c_2 m_2(?-t_1)

here m_1 and c_1 - specific heat and mass of water in the calorimeter, and c_2 m_2 - specific heat and mass of the material of the calorimeter.

This equation expresses the balance of thermal energy, is called the equation of thermal balance. He will find

c=(Q_1+Q_2)/m(t- ?) =( c_1 m_1 (?-t_1)+ c_2 m_2(?-t_1))/m(t- ?) = (c_1 m_1+m_2 c_2)( ?- t_1)/m(t- ?)